0.05=y^2+0.05y

Solution for 0.05=y^2+0.05y equation:

0.05=y^2+0.05y

We move all terms to the left:

0.05-(y^2+0.05y)=0

We get rid of parentheses

-y^2-0.05y+0.05=0

We add all the numbers together, and all the variables

-1y^2-0.05y+0.05=0

a = -1; b = -0.05; c = +0.05;
Δ = b2-4ac
Δ = -0.052-4·(-1)·0.05
Δ = 0.2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.05)-\sqrt{0.2025}}{2*-1}=\frac{0.05-\sqrt{0.2025}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.05)+\sqrt{0.2025}}{2*-1}=\frac{0.05+\sqrt{0.2025}}{-2}
$